Speed Dog
a dog to the north due to a constant speed of 2 meters per second jog past a fire hydrant?
a dog to the north due to a constant speed 2 meters per second jog past a fire hydrant at t = 0 sec. Another dog heading due east at a constant speed of 3 meters per second jog through the mouth irrigation at time t = 1 sec. At t = 9 sec., What is the rate of change of distance between the two dogs?
Place the hydrant in origin (0, 0). Then, at time t = 9 sec. the dog to the north is at the point (0, 18). The dog East bound, which passes through a hydrant sec. later, is now at the point (27, 0). Rate of change is calculated as the slope. (Difference of the values y) / (x difference of values.) So this becomes (18-0) / (0-27), which = 18/-27 or -2 / 3. Good luck!
Speed painting dog portrait in pastel (Setter)
